[" If "A,B,C" are the vertices of a triangle whose position "],[" vectors are "a,b,c" and "G" is the centroid of the "Delta ABC," then "],[vec GA+vec GB+vec GC" is "]

If A, B, C are the vertices of a triangle whose position vectors are vec a, vec b, vec c and G is the centroid of the triangle ABC, then vec GA + vec GB + vec GC =

If G is the centroid of Delta ABC then vec(G)A + vec(G)B + vec(G)C =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If A, B, C are the vertices of a triangle whose position vectros are vec a,vec b, vec c and G is the centroid of the DeltaABC, then overline(GA)+overline(GB)+overline(GC) =

If A, B, C are vertices of a triangle whose position vectors are vec a, vec b and vec c respectively and G is the centroid of Delta ABC, " then " vec(GA) + vec(GB) + vec(GC), is

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If G is the centroid of a triangle ABC, prove that vec GA+vec GB+vec GC=vec 0

If G is centroid of the triangle ABC, then find vec(GA)+vec(GB)+vec(GC).