If `1+sinx+sin^2x+sin^3x+oo` is equal to `4+2sqrt(3),0ltxltpi,` then `x`is equal to

Explanation

To solve the problem, we need to find the value of \( x \) such that

\[ 1 + \sin x + \sin^2 x + \sin^3 x + \ldots = 4 + 2\sqrt{3} \]

where \( 0 < x < \pi \).

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