((1)/(2)Rq-(3)/(2)q)times(pq-q)

((1) / (2) pq- (3) / (2) q) xx (pq-q)

sin alpha =(2pq)/(p^2+q^2) => sec alpha - tan alpha= .......... A) (p-q)/(p+q) B) (pq)/(p^(2) +q^(2)) C) (p+q)/(p-q) D) (pq)/(P+q)

A transvers axis cuts the same branch of a hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 at P and P' and the asymptotes at Q and Q'. Prove that PQ=P'Q' and PQ'=P'Q.

A transversal cut the same branch of a hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 in P,P' and the anymptotes in Q.Q' ,the value of (PQ+PQ')-(P'Q'-P'Q)

If two positive integers m and n are expressible in the form m=pq^(3) and n=p^(3)q^(2), where p,q are prime numbers, then HCF(m,n)=pq(b)pq^(2)(c)p^(3)q^(3)(d)p^(2)q^(3)

show that (4pq+3q)^(2)-(4pq-3q)^(2)=48pq^(2)

Simplify ((q^(3-7)q xx q^(6-2q))/(q^(2q)xx q^(9-2q)))^((1)/(9))

In Q.No.7,HCF(a,b) is pq(b)p^(3)q^(3)(c)p^(3)q^(2) (d) p^(2)q^(2)