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For `n in Z ,` the general solution of `(sqrt(3)-1)sintheta+(sqrt(3)+1)costheta=2i s(n in Z)` `theta=2npi+-pi/4+pi/(12)` `theta=npi+(-1)^npi/4+pi/(12)` `theta=2npi+-pi/4` `theta=npi+(-1)^npi/4-pi/(12)`

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`(sqrt3-1)sintheta+(sqrt3+1)costheta=2`
`((sqrt3-1)/(2sqrt2))sintheta+((sqrt3+1)/(2sqrt2))costhe ta=2/(2sqrt2`
`sinpi/12sintheta+cospi/12costheta=cospi/7`
`cos(theta-pi/7)=cospi/4`
`theta-pi/2=2npipmpi/4`
`theta=2npipmpi/4+pi/12`.
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