suppose cosA is given if only one value of cos(A/2 ) is possible then A is must be

Suppose cos A is given. If only one value of cos (A/2) is possible, then A must be:

If sinA+cosA=sqrt(2), then the value of cos^(2) A is

If cosA=3/5 , then find the value of (sinA-cosA)/(2tanA)

The value of 2sinA cos^(3)A -2sin^(3)A cosA is

The value of 2sinA cos^(3)A -2sin^(3)A cosA is

Given 5 cos A - 12 sin A = 0 , evaluate : (sinA+cosA)/(2 cosA-sinA)

When any two sides and one of the opposite acute are given, under certain additional condition two triangle are possible. The case when two triangle are possible is called the ambiguous case. In fact when any two sides and the angle opposite to one of them are given either no triangle is possible or only one triangle is possible or two triangle are possible. In the ambiguous case, let a, b, and angleA are given and c_1,c_2 are two values of the third side c The difference between two values of c is