The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction `2A+4Brarr3C+4D`, when 5 moles of A react with 6 moles of B, then
(a) which is the limiting reagent?
(b) calculate the amount of C formed?

Explanation

`2A + 4B rarr 3C + 4D`
According to the above equation, 2 moles of ‘A’ require 4 moles of ‘B’ for the reaction. Hence, for 5 moles of ‘A’, the moles of ‘B’ required = = 10 mol B
But we have only 6 moles of ‘B’, hence, ‘B’ is the limiting reagent. So amount of ‘C’ formed is determined by amount of ‘B’.
Since 4 moles of ‘B’ give 3 moles of ‘C’. Hence 6 moles of ‘B’ will give 6 mol of `B xx ("3 mol of C")/("4 mol of B") = 4.5 mol` of C