Calculate the average atomic mass of hydrogen using the following data :
`{:("Isotope","% Natural abudance mass","Atomic mass(amu)"),(.^(1)H," "99.985," "1),(.^(2)H," "0.015," "2):}`

Explanation

Average Atomic Mass
`({("Natural abundance of ".^(1)H xx "molar mass")+("Natural abundance of ".^(2)H xx " molar mass of ".^(2)H)})/(100) = (99.985 xx 1 + 0.015 xx 2)/(100)`
`= (99.985 + 0.030)/(100) = (100.015)/(100) = 1.00015 u`