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The number of atoms present in a 0.635 g...

The number of atoms present in a 0.635 g of Cu piece will be :

A

`6.023 xx 10^(-23)`

B

`6.023 xx 10^(23)`

C

`6.023 xx 10^(22)`

D

`6.023 xx 10^(21)`

Text Solution

Verified by Experts

The correct Answer is:
D
No. of atoms `= (0.635)/(63.5) xx 6.023 xx 10^(23) = 6.023 xx 10^(21)`
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