0.1 g of metal combines with 46.6 mL of ...

`0.1 g` of metal combines with `46.6 mL` of oxygen at `STP`. The equivalent weight of metal is

A

12

B

24

C

6

D

36

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The correct Answer is:

A

Meq. of metal = Meq. of oxygen , `1000 xx (0.1)/(E) = (46.6)/(22400) xx 1000 xx 2 xx rArr E = 12`

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