The amount of `BaSO_(4)` formed upon mixing 100mL of 20.8% `BaCl_(2)` solution with 50mL of 9.8% `H_(2)SO_(4)` solution will be :
(Ba = 137, Cl = 35.5, S = 32, H = 1 and O =16)

Options

A. 23.3g
B. 11.65 g
C. 30.6 g
D. None of these

Answer

B

Explanation

`{:(,BaCl_(2),+,H_(2)SO_(4),rarr,BaSO_(4),+,2HCl),("Initially","0.1 moles",,"0.05 moles",,-,,-),("Finally",0.05,,-,,0.5,,0.1):}`
Mass of `BaSO_(4) = 0.05 xx 233 = 11.65 g`