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0.5 mole of H(2)SO(4) is mixed with 0.2 ...

`0.5` mole of `H_(2)SO_(4)` is mixed with `0.2` mole of `Ca(OH)_(2)`. The maximum number of mole of `CaSO_(4)` formed is:

A

0.2

B

0.5

C

0.4

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
A
Eq. of `H_(2)SO_(4) = 0.5 xx 2 = 1.0` , Eq. of `Ca(OH)_(2) = 0.2 xx 2 = 04`
Equal equivalents reacts, thus `CaSO_(4)` formed = 0.4
`:.` Mole of `CaSO_(4)` formed `= (0.4)/(2) = 0.2`
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