How many moles of O are present in 4.9 g...

How many moles of `O` are present in `4.9 g` of `H_(3) PO_(4)`? (Atomic weight of `P, O` and `H = 31, 16, 1`)

A

0.1

B

0.2

C

0.3

D

0.4

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The correct Answer is:

B

Moles of `H_(3)PO_(4) = (4.9)/(98) = (1)/(20) = 0.05`, Moles of `O = 4 xx 0.05 = 0.2`

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