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0.05 g of a piece of metal in dilute aci...

`0.05 g` of a piece of metal in dilute acid gave `24.62 mL` of `H_(2)` at `27^(@)C` and `760mm` pressure. The `Ew` of metal is

A

25

B

12.5

C

50

D

37.5

Text Solution

Verified by Experts

The correct Answer is:
A
Meq. of metal = Meq of `H_(2) rArr 1000 xx (0.05)/(E) = (24.62)/(24620) xx 1000 xx 2 rArr E= 25`
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