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What is the number of moles of Fe(OH)(3)...

What is the number of moles of `Fe(OH)_(3)` (s) that can be produced by allowing 1 mole of `Fe_(2)S_(3)`, 2 moles of `H_(2)O` and 3 moles of `O_(2)` to react as : `2Fe_(2)S_(3) + 6H_(2)O + 3O_2 rarr 4Fe(OH)_(3) + 6S` ?

A

1 mol

B

1.84 mol

C

1.34 mol

D

1.29 mol

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,2Fe_(2)S_(3),+,6H_(2)O,+,3O_(2),rarr,4Fe(OH)_(3),+,6s),("Initially","1 moles",,"2 moles",,"3 moles",,,,):}`
`H_(2)O` is limiting reagent. So, moles of `Fe(OH)_(3) = (4)/(6) xx 2 rArr 1.34`
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