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NO reacts with O(2) to form NO(2). When ...

NO reacts with `O_(2)` to form `NO_(2)`. When 10 g of `NO_(2)` is formed during the reaction, the mass of `O_(2)` consumed is

A

`1.90 g`

B

`5.0 g`

C

`3.48 g`

D

13.9 g

Text Solution

Verified by Experts

The correct Answer is:
C

`2NO + O_(2) rarr 2NO_(2) " "2 mol NO_(2) = 92 g NO_(2) -= 32g O_(2)`
`:. 10 g NO_(2) -= (32)/(92) xx 10g O_(2) = 3.48 g O_(2)`
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