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The mass of N(2)F(4) produced by the ...

The mass of `N_(2)F_(4)` produced by the reaction of 2.0 g of `NH_(3)` and 8.0 g `F_(2)` is 3.56 g. What is the per cent yield ?

A

`79.0`

B

`71.2`

C

`84.6`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,2NH_(3),+,5F_(2),rArr,N_(2)F_(4),+,6HF),("Initially",(2)/(17)"moles",,(8)/(18) "moles",,-,,-),("Finally",-,,(8)/(18)-(2)/(17)"moles",,(1)/(17)"moles",,):}`
mass of `N_(2) F_(4) = (1)/(17) xx 100 = 5.9 g`
% yield `= (3.56)/(5.9) xx 100% = 60%`
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