How many moles of ferric alum
`(NH_(4))_(2) SO_(4) Fe_(2) (SO_(4))_(3). 24 H_(2)O` can be made from the sample of `Fe` containing `0.0056 g` of it?

Options

A. `10^(-4)` mol
B. `0.5 xx 10^(-4)` mol
C. `0.33 xx 10^(-4)` mol
D. `2 xx 10^(-4)` mol

Answer

B

Explanation

Mole of `Fe = (0.0056)/(56) = 0.0001 = 10^(-4)` moles. So, moles of ferric alum `= 0.5 xx 10^(-4)` moles.