27 g of Al will react completely with…… ...

`27 g` of `Al` will react completely with…… `g` of `O_(2)`

A

8g

B

10g

C

24 g

D

49 g

Verified by Experts

The correct Answer is:

A

`2Al + (3)/(2)O_(2) rarr Al_(2)O_(3) " Initially 1 mole " (3)/(4) " moles " :. (3)/(4) xx 32 = 24g`

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