`1.0 g` of a monobasic acid when completely acted upon `Mg` gave `1.301 g` of anhydrous `Mg` salt. Equivalent weight of acid is

Options

A. 35.54
B. 36.54
C. 17.77
D. 18.27

Answer

A

Explanation

`("Eq. wt. of acid")/("Eq. wt. of salt of Mg") = ("Weight of acid")/("Weight of salt")`
Mg + 2HCl (monobasic acid) `rarr MgCl_(2) + H_(2)`
Let Equivalent weight of acid = Equivalent weight of H + Equivalent weight of acid radical
`:.` Equivalent weight of salt of Mg = Equivalent of Mg + Equivalent weight of acid radical
`:. ("Equivalent weight")/("Equivalent weight of M salt") = ("Weight of acid")/("Weight of Mg acid")`
`rArr ("Equivalent weight of H + Equivalent weight of acid radical (E)")/("Equivalent weight of Mg + Equivalent weight of acid radical (E)") = (1.0)/(1.301)`
`rArr (1+E)/(12+E) = (1.0)/(1.301) :. E = 35.54`
`:.` Equivalent weight of acid = Equivalent weight of H + Equivalent weight of acid radical = 1 + 35.54 = 36.54