Home
Class 12
CHEMISTRY
0.1 g of metal combines with 46.6 mL of ...

`0.1 g` of metal combines with `46.6 mL` of oxygen at `STP`. The equivalent weight of metal is

A

12

B

24

C

6

D

36

Text Solution

Verified by Experts

The correct Answer is:
A
1 mol of `O_(2) = 4` eq. of O 22400 mL of `O_(2) 4` eq. of O
`46.6 mL` of `O_(2) = (4)/(22400) xx 46.6 = 0.00832 eq.` Equivalent of metal = Equivalent of O
`("Weight")/("Equivalent weight") = 0.00832 " "(0.1)/(E) = 0.00832 " " :." " E = (0.1)/(0.00832) = 12.0`
Promotional Banner

Similar Questions

Explore conceptually related problems

Equivalent weight of Calcium metal is

A metal oxide has 40% oxygen. The equivalent weight of the metal is:

1.0 g of a metal combines with 8.89 g of Bromine. Equivalent weight of metal is nearly (at.wt. of Br = 80)

0.5g of a metal on oxidation gave 0.7 g of its oxide. The equivalent weight of the metal is -

If the weight of metal oxide is x g containing y g of oxygen, the equivalent weight of metal will be