Home
Class 12
CHEMISTRY
0.05 g of a piece of metal in dilute aci...

`0.05 g` of a piece of metal in dilute acid gave `24.62 mL` of `H_(2)` at `27^(@)C` and `760mm` pressure. The `Ew` of metal is

A

25

B

`12.5`

C

50

D

`37.5`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of `H_(2)` at STP `= 24.62 xx (273)/(300) = 22.40 mL`
22400 mL of `H_(2)` at STP = 1 mole = 2 Equivalent of `H_(2)`
22.4 mL of `H_(2) = (2)/(22400) xx 22.4 = 0.002` equivalent of `H_(2) = 0.002` equivalent of metal
`:. ("Weight")/("Equivalent weight") = 0.02 rArr (0.05)/(0.002) = "Equivalent weight" = 25`
Promotional Banner

Similar Questions

Explore conceptually related problems

2 gm of O_(2) at 27^(@)C and 760 mm of Hg pressure has volume "____________" .

10g of mixture of hexane and ethanol is reated with Na to give 200 ml of hydrogens at 27^(@)C and 760mm Hg pressure. What is the percentage of ethanol in the mixture.

When dissolved in dilute H_(2)SO_(4), 0.275 g of metal evolved 119.7 mL of H_(2) at 20^(@)C and 780.4 mm pressure. H_(2) was collected over water. Aqueous tension is 17.4 mm at 20^(@)C . Calculate equivalent weight of metal.

0.27g of an organic compound gave on combustion 0.396 of CO_(2) 0.216g of H_(2)O 0.36g of the same substance gave 48.88 ml of N_(2) at 290K and 740mm pressure Calculate the percentage composition of the compound.