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10 g of a sample of a mixture of CaCl(2)...

`10 g` of a sample of a mixture of `CaCl_(2)` and `NaCl` is treated to precipitate all the calcium as `CaCO_(3)`. This `CaCO_(3)` is heated to convert all the `Ca` to `CaO` and the final mass of `CaO` is 1.62 g.The percent by mass of `CaCl_(2)` in the origial mixture is

A

`32.1%`

B

`16.2%`

C

`21.8%`

D

`11.0%`

Text Solution

Verified by Experts

The correct Answer is:
A
`CaCl_(2) + NaCl = 10g`, Let weight of `CaCl_(2) = xg`
`{:(CaCl_(2), rarr ,CaCO_(3) ,rarr ,CaO),("1 mol",,"1 mol",,"1 mol"),((x)/(111) "mol",,(x)/(111)"mol",,(x)/(111)"mol"):}`
Mole of `CaO = (1.62)/(56) :. (x)/(11) = (1.62)/(56) rArr x = 3.21 g , " "% of CaCl_(2) = (3.21)/(10) xx 100 = 32.1 %`
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