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13.4 g of a sample of unstable hydrated ...

`13.4 g` of a sample of unstable hydrated salt `Na_(2)SO_(4).XH_(2)O` was found to contains `6.3 g` of `H_(2) O`. The number of molecular of water of crystalistion is

A

5

B

7

C

2

D

10

Text Solution

Verified by Experts

The correct Answer is:
B
Weight of salt = 13.4 g, Weight of `H_(2)O = 6.3 g`
Weight of anhydrous salt = 13.4 – 6.3 = 7.1 g
Moles of anhydrous salt `= (7.1)/(142) = 0.05` , Moles of `H_(2)O = (6.3)/(18) = 0.35` mol
0.05mol of anhydrous `rArr` salt 0.35 mol of `H_(2)O` , For 1 mole `rArr` 7 mole `H_(2)O`
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