Home
Class 12
CHEMISTRY
A mineral consists of an equimolar mixtu...

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 15.0% by weight, `3.0 g` of the mineral on heating lost `1.10 g` of `CO_(2)`. The percent by weight of other metal is

A

65

B

25

C

75

D

35

Text Solution

Verified by Experts

The correct Answer is:
D
`MCO_(3) rarr MO + CO_(2) uarr , M'CO_(3) rarr M'O + CO_(2) uarr`
Equation of `CO_(2)` = Equation of carbonates of metals
1 mol of `CO_(2) = 1` mol of `CO_(3)^(2-)` , 44 g of `CO_(2) = 60 g` of `CO_(3)^(2-)`
1.10 g of `CO_(2) = (60)/(44) xx 1.10 = 1.5g` of `CO_(3)^(2-)` , % of `CO_(3)^(2-) = (1.5 xx 100)/(3) = 50%`
% of one metal = 15% , % of another metal = 100 - 50 - 15 = 35%
Promotional Banner

Similar Questions

Explore conceptually related problems

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by mass.2.8 g of the mineral on heating loat 1.32g of CO_(2) . What is the % by mass of the other metal ?

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by mass 2.8g of the mineral on heating lost 1.32g of CO_2 . What is the % by mass of the other metal ?

A mixture contains equi-molar quantities of carbonates of two bivalent metals. One metal is present the extent of 13.5% by weight in the mixture and 2.50 g of the mixture on heating leaves a residue of 1.18 g . Calculate the percentage by weight of the other metal.

0.5g of a metal on oxidation gave 0.7 g of its oxide. The equivalent weight of the metal is -