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10 mL of 1 M BaCl(2) solution and 5 ml ...

`10 mL` of `1 M BaCl_(2)` solution and `5 ml ` of `0.5 M K_(2)SO_(4)` are mixed together ot precipitate out `BaSO_(4)`. The amount of `BaSO_(4)` precipated will be

A

0.005 mol

B

0.00025 mol

C

0.025 mol

D

0.0025 mol

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(BaCl_(2),+,K_(2)SO_(4),rarr,BaSO_(4)darr,+,2KCl),(10 xx 1,,5 xx 0.5,,,,),(="10 m mol",,= "2.5 m mol",,,,):}`
Here, `K_(2)SO_(4)` is the limiting reagent, 1 mmol `K_(2)SO_(4) -= 1` mmol `BaSO_(4)`
2.5 m mol `K_(2)SO_(4) -= 2.5 m` mol `BaSO_(4) = (2.5)/(1000) = 0.0025` mol `BaSO_(4)`
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