Home
Class 12
CHEMISTRY
Specific gravity of a salt solution is 1...

Specific gravity of a salt solution is 1.025. Quantity of the solution required that consist of 1 mole of solute `(M^(@) = 60)` if molarity of the original solution is 0.9M.

A

1008 g

B

1138 g

C

1492 g

D

997 g

Text Solution

Verified by Experts

The correct Answer is:
B
as `M = (10 xd)/(M^(@)), 0.9 = (10 xx x xx 1.025)/(60) , x = 5.27`
`rArr` 5.27 gm of salt in 100g solution. `rArr` 60 gm of salt in `((100)/(5.27))60 = 1138g` solution.
Promotional Banner

Similar Questions

Explore conceptually related problems

Molar solution means 1 mole of solute present in

M = molarity of the solution m = molality of the solution d = density of the solution (in g. ml^(-1) ) M^(-1)= gram molecular weight of solute Which of the following relations is correct

2.5 litre of 1M NaOH solution is mixed with another 3 litre solution of 0.5M NaOH solution. Then the molarity of the resulting solution is

The specific gravity of a salt solution is 1.025. If V mL of water is added to 1 L of this solution to make its density 10.2 g mL^(-1) , what value of V in mL approxmately?

If X is the conductivity of the solution and M is the molarity of the solution, the molar conductivity of the solution is given by ________.

In a solution of ethanol in water, the mole fraction of ethanol is 0.05 and the density of solution is 1.94 g mL^(-1) . The molarity of the solution is ___ M