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If 100 mL of H(2) SO(4) and 100 mL of H(...

If `100 mL` of `H_(2) SO_(4)` and `100 mL` of `H_(2)O` are mixed, the mass percent of `H_(2) SO_(4)` in the resulting solution `(d_(H_(2)SO_(4)) = 0.9 g mL^(-1), d_(H_(2)O) = 1.0 gmL^(-1))`

A

90

B

47.36

C

50

D

60

Text Solution

Verified by Experts

The correct Answer is:
B
Mass % of `H_(2)SO_(4) = ((0.9 xx 100))/((0.9 xx 100) + (1 xx 100)) xx 100% = (90)/(90 + 100) xx 100% = (90)/(190) xx 100% = 47.36%`
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