Home
Class 12
CHEMISTRY
50 mL of a solution containing 1 g each ...

50 mL of a solution containing 1 g each of `Na_(2)CO_(3), NaHCO_(3)` and NaOH was titrated with N-HCl. What will be the titre reading when only phenolphalein is used as indicator?

A

35 ml

B

32.5 ml

C

24.5 ml

D

34.4 ml

Text Solution

Verified by Experts

The correct Answer is:
D

At the end point using phenolphthalein as indicator uses complete NaOH and `(1)/(2)` Meq. of `Na_(2)CO_(3)`.
`:.` Meq of `NaOH + (1)/(2) "Meq of " Na_(2)CO_(3) = "Meq of HCl"`
`(1)/(40) xx 1000 + (1)/(2) xx (1)/(106) xx 2 xx 1000 = V xx 1 :. V = 34.4 ml`
Promotional Banner

Similar Questions

Explore conceptually related problems

50 " mL of " a solution containing 1 g each of Na_2CO_3 , NaHCO_3 and NaOH was titrated with N HCl. What will be the titre value if: (a). Only phenolphthalein is used as an indicator? ltbr. (b). Only methyl orange is used as an indicator from the very begining? (c). Methyl orange is added after the first end point with phenolphthalein?

20 mL of 0.1 M solution of compound NaCO_(3).NaHCO_(3).2H_(2)O is titrated against 0.05 M HCL. X mL of HCL is used when phenolphthalein is used as an indicator and y mL of HCL is used when methly orange is the indicator in two separate titrations. Hence (y-x) is: