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Calculate the volume of O(2) and volume ...

Calculate the volume of `O_(2)` and volume of air needed for combustion of `1 kg` carbon at `STP`.

A

1866.6, 8888.5

B

1866.6, 8433.35

C

1866.6, 7233.35

D

3666.6, 9433.35

Text Solution

Verified by Experts

The correct Answer is:
A
`C + O_(2) rarr CO_(2)`
1mol C `-= 1 mol O_(2) = 22.4 L O_(2)` gas at STP
`(1000)/(12) = mol C -= 22.4 xx (1000 L)/(12)O_(2)` gas at STP = 1866.6 L
Volume of air `= (1866.6)/(0.21) = 8888.5 L`
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