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What volume of 90% alcohol by weight (d ...

What volume of 90% alcohol by weight `(d = 0.8 g mL^(-1))` must be used to prepared `80 mL` of 10% alcohol by weight `(d = 0.9 g mL^(-1))`

A

10

B

20

C

30

D

40

Text Solution

Verified by Experts

The correct Answer is:
A
Mass of alcohol in `2^(nd)` solution `= (1)/(100) xx 80 xx 0.9 = 7.2 g`
Mass of alcohol in `1^(st)` solution `= (90)/(100) xx v xx 0.8 = (7.2v)/(10)g , " Now, " 7.2 = (7.2 v)/(10) rArr v = 10 mL`
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