Home
Class 12
CHEMISTRY
When a mixture of 10 moles of SO(2) and ...

When a mixture of 10 moles of `SO_(2)` and 15 moles of `O_(2)` was passed over catalyst, 8 moles of `SO_(3)` was formed. How many moles of `SO_(2)` and `O_(2)` did not enter into combination?

A

`n_(SO_(2)) = 10, n_(O_(2)) = 10`

B

`n_(SO_(2)) = 10, n_(O_(2)) = 7.5`

C

`n_(SO_(2)) = 2, n_(O_(2)) = 7.5`

D

`n_(SO_(2)) = 4, n_(O_(2)) = 11`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,2SO_(2),+,O_(2),rarr,2SO_(3)),("Initially","20 moles",,"15 moles",,-),("Finally","10 moles",,"10 moles",,"10 moles"):}`
Promotional Banner

Similar Questions

Explore conceptually related problems

When a mixture of 10 moles of SO_(2) and 16 moles of O_(2) were passed over a catalyst, 8 moles of SO_(3) were formed at equilibrium. The number of SO_(2) and O_(2) remaining unreacted were:

When a mixture consisting of 10 moles of SO_2 and 16 moles of O_2 were passed over a catalyst , 8 mole of SO_3 were formed at equilibrium.The number of moles of SO_2 and O_2 which did not enter into reation were :

10 "mole of" kSO_(2) and 15 "mole of" O_(2) were passed over catalyst to produce 8 "mole of" SO_(3) . The ratio of SO_(2) and SO_(3) moles in mixture is:

10 moles SO_(2) and 15 moles O_(2) were allowed to react over a suitable catalyst. 8 moles of SO_(3) were formed. The remaining moles of SO_(2) and O_(2) respectively are -

1 mole of [OH^(-)] is present in how many moles of H_(2)O ?

How many moles are in 96 g O_(2)?

A mixture containing one mole of BaF_(2) and two mole of H_(2)SO_(4) will be neutralised by: