Home
Class 12
CHEMISTRY
The number of mole of N(2)O(4) in 276 g...

The number of mole of `N_(2)O_(4)` in 276 g `N_(2)O_(4)` are …..

Text Solution

Verified by Experts

The correct Answer is:
3
`M = (g)/(M_(0)) = (276)/(92) = 3`
Promotional Banner

Similar Questions

Explore conceptually related problems

8 mole of a mixture of N_(2), NO_(2) and N_(2)O_(4) has a mean molecular mass of (378)/(8) . On heating to a temperature at which N_(2)O_(4) dissociated completely (N_(2)O_(4)rarr 2NO_(2)) , the mean molecular mass become (378)/(9) . The ratio of number of moles of N_(2): NO_(2):N_(2)O_(4) in original mixture is :

One mole of a mixture of N_(2),NO_(2) and N_(2)O_(4) , has a mean molar mass of 55.4 . On heating to a temperature at which N_(2)O_(4) may be dissociated :N_(2)O_(4)rarr2NO_(2) , the mean molar mass tends to the lower value of 39.6 . What is the mole ratio of N_(2) : NO_(2) : N_(2)O_(4) in the original mixture?

8 mole of a mixture of N_(2), NO_(2) and N_(2)O_(4) has a mean molecular mass of (378)/(8) . On heating to a temperature at which N_(2)O_(4) dissociated completely (N_(2)O_(4)rarr 2NO_(2)) , the mean molecular mass become (378)/(9) . The ratio of number of moles of N_(2) and NO_(2) after heating is :

A mixture of n_(1) moles of Na_(2)C_(2)O_(4) and NaHC_(2)O_(4) is titrated separately with H_(2)O_(2) and KOH , to reach at equivalence point. Which of the following statement is/are correct?

For the reaction: N_(2)O_(4)(g)rarr2NO_(2)(g) the number of moles of N_(2)O_($)(g) with time given as : |{:("Time, min","0","5","10"),("Moles N"_(2)O_(4)(g),"0.200","0.170","0.140"):}| What is the number of moles of NO_(2)(g) at t=10 min? (Assume moles of NO_(2)(g)=0 at t = 0)