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A given sample of pure compound contains...

A given sample of pure compound contains `9.81 g` of Zn, `1.8xx10^(23)` atoms of chromium, and `0.60` mol of oxygen atoms. What is the simplest formula?

Text Solution

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The correct Answer is:
4
`ZnCr_(2)O_(x), Zn : Cr : O = 1:2 :x`
So for `1.8 xx 10^(23)` atoms of Cr i.e. 0.3 mol of `Cr, (0.3)/(2) xx x` mol of O atoms must be present.
`(0.3)/(2) xx x = 0.6 rArr x = 4`
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