Home
Class 12
CHEMISTRY
1g of a carbonate (M(2)CO(3)) on treatme...

`1g` of a carbonate `(M_(2)CO_(3))` on treatment with excess `HCl` produces `0.01186` mole of `CO_(2)`. The molar mass of `M_(2)CO_(3)` in `g mol^(-1)` is

A

11.86

B

1186

C

84.3

D

118.6

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,M_(2)CO_(3),+,2HCl,rarr,2MCl,+,H_(2)O,+,+CO_(2)),("Molar ratio",1,:,,,,,1,,):}`
`(1g)/(2M + 60)` moles yield `(1)/(2M + 60)` moles `CO_(2) = 0.01186` (given) `rArr M = 84.3`
Promotional Banner

Similar Questions

Explore conceptually related problems

1 gram of carbonate (M_(2)CO_(3)) on treatment with excess HCl produces 0.1186 mole of CO_(2) . The molar mass of M_(2)CO_(3) "in g mol"^(-1)

4 g of an impure sample of CaCO_(3) on treatment with excess HCl produces 0.88 g CO_(2) . What is per cent purity of CaCO_(3) sample?

62.5 gm of a mixture of CaCO_(3) and SiO_(2) are treated with excess of HCl and 1.1 gm of CO_(2) is produced. What is mass % CaCO_(3) in the mixture.