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For the following reaction, the mass of ...

For the following reaction, the mass of water produced from 445 g of `C_(57)H_(110)O_(6)` is :
`2C_(57)H_(110)O_(6)(s)+163O_(2)(g) to 114CO_(2)(g)+110H_(2)O(l)`

A

445 g

B

495 g

C

890 g

D

490 g

Text Solution

Verified by Experts

The correct Answer is:
B
`2C_(57)H_(110)O_(6)(s) + 1630O_(2)(g) rarr 114CO_(2)(g) + 110H_(2)O(l)`
Moles of `C_(57)H_(10)O_(6) = (445)/(890) = (1)/(2) = 0.5` mol
As molar mass of `C_(57)H_(110)O_(6) = 890g//mol`
So, mass of `H_(2) = (110)/(2) xx 0.5 = 495 g`
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