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50 mL of 0.5 M oxalic acid is needed to ...

50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is _________.

A

80g

B

20 g

C

10 g

D

4 gm

Text Solution

Verified by Experts

The correct Answer is:
D
Answer is not in the options hence BONUS
Number of gram equivalents of `H_(2)C_(2)O_(4)` = Number of gram equivalents of NaOH
`rArr 50 xx 0.5 xx 2 = 25 xx x xx 1 rArr x = (50 xx 0.5 xx 2)/(25) = 2M`
`M = 2 = (W)/(40) xx (1000)/(50) rArr W = (2 xx 40 xx 50)/(1000) = 4gm`
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