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At 300 K and 1 atmospheric pressure, 10 ...

At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of `O_(2)` for complete combustion, and 40 mL of `CO_(2)` is formed. The formula of the hydrocarbon is:

A

`C_(4)H_(6)`

B

`C_(4)H_(7)Cl`

C

`C_(4)H_(10)`

D

`C_(4)H_(8)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,C_(x)H_(y),+,(x+(y)/(4))O_(2(g)),rarr,xCO_(2(g)),+,(y)/(2)H_(2)O_((l))),("Initial condition",10 ml,,55 ml,,0,,0),("After reaction",0,,0,,40ml,,-):}`
From stoichiometry concept,
`{:(10(x+(y)/(4)) = 55|,10x = 40 rArr x = 4 , rArr, 10x + 10(y)/(4) = 55),(10x + (10y)/(4)=55,y=(15 xx 4)/(10),:.,y = 6):}`
Hence `C_(x)H_(y) rArr C_(4)H_(6)`
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