The number of electrons present in of water is ______________.

Answer

`6.023 xx 10^(24)`

Explanation

`6.023 xx 10^(24)`
18 ml of `H_(2)O rArr 18 gm H_(2) O rArr` 1 mole `H_(2)O` (d = 1 gm/ml)
1 molecule of `H_(2)O` has `underset("(of H-atom)")(1e^(-) xx 2) + underset("of H-atom)")(8e^(-)) = 10e^(-) :. " "` 1 mole `H_(2)O` has 10 moles `e^(-) rArr 6.022 xx 10^(24)e^(-)`