The weight of `1 xx 10^(22)` molecules of `CuSO_(4). 5H_(2)O` is

Answer

4.14 g

Explanation

Molar mass of `CuSO_(4).5H_(2)O = 63.5 + 32 + 4 xx 16 + 5 xx 18 = 249.5 g`
Also, molar mass represents mass of Avogadro number of molecules in gram unit, therefore
`because 6.023 xx 10^(23)` molecules of `CuSO_(4).5H_(2)O` weight 249.5 g
`:. 10^(22)` molecules will weight `(249.5)/(6.023 xx 10^(23)) xx 10^(22) = 4.14 g`