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29.2% (w//w) HCl stock, solution has a d...

`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`. The molecular weight of `HCl` is `36.5 g mol^(-1)`. The volume `(mL)` of stock solution required to prepare a `200 mL` solution of `0.4 M HCl` is :

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The correct Answer is:
8
29.2 % w/w
Molarity `= (10 xd)/(M_(0)) = (10 xx 29.2 xx 1.25)/(36.5) = 10 M`
Since, Number of m moles of HCl is conserved `10 M xx V_(ml) = 200 xx (4)/(10) rArr V_(ml) = 8m l`
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