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A 25 watt bulb emits monochromatic yello...

A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57`mum`. Calculate the rate of emissionn of quanta per second.

Text Solution

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Energy emitted by the bulb = 25 watt `=25Js^(-1)" "("1 watt "=1Js^(-1))`
Energy of one photon `(E)=hv=h(c)/(lambda)" Here. "lambda=0.57mu m = 0.57xx10^(-6)m`
Putting `c=3xx10^(8)ms^(-1), h=6.62xx10^(-34)"J s, we get E"=((6.62xx10^(-34)Js)(3xx10^(8)ms^(-1)))/(0.57xx10^(-6)m)=3.48xx10^(-19)J`
No. of photon emitted per sec `=(25Js^(-1))/(3.48xx10^(-19)J)=7.18xx10^(19)`
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