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The principal quantum number of H-atom o...

The principal quantum number of H-atom orbital, if the energy of `e^(-)` is `-3.4eV`, will be:

A

1

B

2

C

3

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(n)=-13.6(Z^(2))/(n^(2))" i.e. "-3.4=013.6xx(1^(2))/(n^(2))" "rArr" "n=sqrt((13.6)/(3.4))=2`
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