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According to Bohr’s theory, the angular ...

According to Bohr’s theory, the angular momentum for an electron of `3^("rd")` orbit is:

A

`3(h)/(2pi)`

B

`1.5(h)/(2pi)`

C

`9(h)/(2pi)`

D

`2(h)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Angular Momentum `=(nh)/(2pi)=nh=3h`
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