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The ionization enthalpy of hydrogen atom...

The ionization enthalpy of hydrogen atom is `1.312 xx 10^6 J mol^-1`. The energy required to excite the electron in the atom from `n= 1` to `n = 2` is :

A

`8.51xx10^(5)"J mol"^(-1)`

B

`6.56xx10^(5)"J mol"^(-1)`

C

`7.56xx10^(5)"J mol"^(-1)`

D

`9.84xx10^(5)"J mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`E_(n)prop (1)/(n^(2))," For ionisation "n=1 rarroo, DeltaE ("From "n = 1 rarr2)=1.312xx10^(6)(1-(1)/(4))=9.88xx10^(5)"J mol"^(-1)`
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