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An electron, a proton and an alpha parti...

An electron, a proton and an alpha particle have KE of 16E, 4E and E respectively. What is the qualitative order of their de-Broglie wavelengths?

A

`lambda_(e) gt lambda_(p) gt lambda_(alpha)`

B

`lambda_(p)=lambda_(alpha)gt lambda_(e)`

C

`lambda_(e) gt lambda_(p) =lambda_(alpha)`

D

`lambda_(alpha) gt lambda_(e) gt lambda_(p)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda=(h)/(mv)=(h)/(sqrt(2mK.E.)), lambda_(e)=(h)/(sqrt(2m_(e).16E)), lambda_(p)=(h)/(sqrt(2xx1836m_(e).4E)), lambda_(alpha)=(h)/(sqrt(2xx4xx1836m_(e)xxE))`
`("Since "m_(alpha)~~4m_(p))rArr" "lambda_(e)gt lambda_(p) gt lambda_(alpha)`
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