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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in a d-orbital is:

A

`sqrt6(h)/(2pi)`

B

`sqrt2(h)/(2pi)`

C

`(h)/(2pi)`

D

`(2h)/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
A

For d orbital `l=2, L=sqrt(l(l+1))(h)/(2pi)=(sqrt6h)/(2pi)` where l = orbital angular momentum.
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