On the basis of Bohr’s model, the radius...

On the basis of Bohr’s model, the radius of the `3^("rd")` orbit is :

A

equal to the radius of first orbit

B

three times the radius of first orbit

C

five times the radius of first orbit

D

nine times the radius of first orbit

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The correct Answer is:

D

`r prop (n^(2))/(z),(r_(1))/(r_(2))=((1)^(2))/((3)^(2))" "rArr" "r_(2)=9r_(1)`

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