The first emission line in the H-atom sp...

The first emission line in the H-atom spectrum in the Balmer series appears at:

A

`(9R_(H))/(400)cm^(-1)`

B

`(7R_(H))/(144)cm^(-1)`

C

`(3R_(H))/(4)cm^(-1)`

D

`(5R_(H))/(36)cm^(-1)`

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The correct Answer is:

D

First line in Balmer series is due `n=3 rarrn=2` transition.
`bar(v)=R_(H)((1)/(4)-(1)/(9))=R_(H).(5)/(36)`

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