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Maximum number of electrons in an orbita...

Maximum number of electrons in an orbital having n = 4 and l = 2 are :

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To find the maximum number of electrons in an orbital with quantum numbers n = 4 and l = 2, we can follow these steps: ### Step 1: Identify the Quantum Numbers - The principal quantum number (n) is given as 4. - The azimuthal quantum number (l) is given as 2. ### Step 2: Determine the Subshell - The value of l corresponds to a specific subshell: - l = 0 corresponds to s subshell - l = 1 corresponds to p subshell - l = 2 corresponds to d subshell - Since l = 2, we are dealing with the d subshell. ### Step 3: Use the Formula to Calculate Maximum Electrons - The maximum number of electrons that can occupy a subshell is given by the formula: \[ \text{Maximum Electrons} = 2(2l + 1) \] - Substitute the value of l into the formula: \[ \text{Maximum Electrons} = 2(2 \times 2 + 1) \] ### Step 4: Perform the Calculation - Calculate \(2l + 1\): \[ 2l + 1 = 2 \times 2 + 1 = 4 + 1 = 5 \] - Now substitute this back into the formula: \[ \text{Maximum Electrons} = 2 \times 5 = 10 \] ### Conclusion - The maximum number of electrons that can be accommodated in an orbital with n = 4 and l = 2 is **10**. ---

To find the maximum number of electrons in an orbital with quantum numbers n = 4 and l = 2, we can follow these steps: ### Step 1: Identify the Quantum Numbers - The principal quantum number (n) is given as 4. - The azimuthal quantum number (l) is given as 2. ### Step 2: Determine the Subshell - The value of l corresponds to a specific subshell: ...
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Maximum number of electrons present in these orbitals having at least "'2'" nodes is (I) "n=1,l=0,m_(l)=0],[(II)n=3,l=2,m_(l)=+1],[(III)n=5,l=1,m_(l)=+1],[(IV)n=3,l=2,m_(l)=-1],[" ( "V)n=2,l=1,m_(l)=0]]