In a hydrogen atom, if the energy of an ...

In a hydrogen atom, if the energy of an eelctron in the ground state is 13.6 eV`, then that in the 2nd excited state is

A

1.51 eV

B

3.4 eV

C

6.04 eV

D

13.6 eV

Verified by Experts

The correct Answer is:

A

`2^("nd")` excited state will be the `3^("rd")` energy level.`" "E_(n)=(13.6)/(n^(2))eV or E = (13.6)/(9)=1.51eV`

Similar Questions

Explore conceptually related problems

In a hydrogen atom , If the energy of electron in the ground state is -x eV ., then that in the 2^(nd) excited state of He^(+) is

In a hydrogen atom, if energy atom, if energy of an electron in group state is - 13.6 eV , then that in the 2^(nd) excited state is :

Energy of H-atom in the ground state is -13.6eV . Hence energy in the second excited state is

The energy of the electron in the ground state of H-atom is -13.6 eV . The energy of the first excited state will be

The energy of an atom or ion in the first excited state is -13.6 eV. It may be

energy of an electron system in the first excited state is -13.6 eV. This is

The energy of a hydrogen atom in the ground state is -13.6 eV . The eneergy of a He^(+) ion in the first excited state will be